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Q.

The energy in MeV is released due to transformation of 1 kg mass completely into energy c=3×108m/s

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a

7.625×10MeV

b

10.5×1029MeV

c

2.8×10−28MeV

d

5.625×1029MeV

answer is D.

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Detailed Solution

E=Δmc2=1×3×1082=9×1010J ⇒E=9×10161.6×10−19=5.625×1035eV=5.625×1029MeV
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