Energy needed in breaking a drop of radius R into n drops of radius r, is
4πr2n−4πR2T
4π3nπr2−43πR2T
4πR2−4πr2nT
4πR2−n4πr2T
Energy needed = work done In splitting, the volume remains unchanged∴ 43πR3=43πr3×nor r=R/(n)1/3 Energy needed = W = surface tension x change in area =T4πr2n−4πR2