Energy needed in breaking a drop of radius R into n drops of radii r is given by
4πT(nr2−R2)
43π(r3n−R2)
4πT(R2−nr2)
4πT(nr2+R2)
Energy needed = Increment in surface energy = (surface energy of n small drops) – (surface energy of one big drop)
=n4πr2T−4πR2T=4πT(nr2−R2)