The energy of a particle executing SHM is given b E=Ax2+BV2where x is displacement from mean position and V is velocity. Then

given E=Ax2+BV2  when x=0 velocity is maximum i.e,Rω  where R is the amplitude and ω is the angular frequency    when V=0 it is at maximum displacement x=Rthen  V=0  E=AR2 ;      R=EA    when x=0      E=BV2=BRω2 Rω =Vmax=EB   ω=EB1R =ABtotal energy = E=12mϖ2R2=12mEB m=2B