First slide

Photo Electric Effect

Question

The energy of a photon of light of wavelength 450 nm is:

Moderate

A

$4.4 \times 10^{- 19}$
B

$2.5 \times 10^{- 19}$
C

$1.25 \times 10^{- 17}$
D

$2.5 \times 10^{- 17}$

Solution

$E_{ph} = \frac{1240}{λ (in nm)} eV = \frac{1240}{450} \times 1 .6$
$\times 10^{- 19} = 4 .41 \times 10^{- 19} J$

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