Question

Energy of a satellite in circular orbit is E₀. The energy required to move the satellite in a circular
orbit of 3 times the radius of the initial orbit is

Easy

Solution

$E_{i} = E_{0} = - \frac{G M m}{2 r}$
$or E_{f} = - \frac{G M m}{2 (3 r)} = - \frac{G M m}{6 r}$
$∴ W = E_{f} - E_{i} = - \frac{G M m}{3 r} = \frac{2}{3} E_{0}$

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