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Q.

The energy stored in the capacitor as shown in the figure (a) is 4.5 x 10-4J. If the battery is replaced by another capacitor of 900 pF as shown in figure (b), then the total energy of system is

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a

4.5 x 10-6J

b

2.25 x 10-6J

c

Zero

d

9 x 10-6 J

answer is B.

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Detailed Solution

Ei=1Q22C=4.5×10−6J∵Q=CV=900×10−12×100=9×10−8C  In fig (b) Ceq. =2C=2×900 pF ∴Ef=12Q2CQ=Q22(x)          =12×4.5×10−6=2.25×10−6J
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