Questions
The energy stored in the capacitor as shown in the figure (a) is 4.5 x 10-4J. If the battery is replaced by another capacitor of 900 pF as shown in figure (b), then the total energy of system is
detailed solution
Correct option is B
Ei=1Q22C=4.5×10−6J∵Q=CV=900×10−12×100=9×10−8C In fig (b) Ceq. =2C=2×900 pF ∴Ef=12Q2CQ=Q22(x) =12×4.5×10−6=2.25×10−6JTalk to our academic expert!
Similar Questions
Two identical capacitors, have the same capacitance C. One of them is charged to potential V1 and the other to V2. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is
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