Q.

The energy stored in the capacitor in the steady state is

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a

338  μJ

b

196  μJ

c

98  μJ

d

8  μJ

answer is A.

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Detailed Solution

At steady state, capacitor acts as open circuit.VA + 3 ×  1−14−5 × 3= VB ⇒   VA−VB=26VEnergy stored in capacitor,U=12  CV2 =12   × 10−6  ×  262 =  338  μJ
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The energy stored in the capacitor in the steady state is