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The energy stored in the capacitor in the steady state is

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338 μJ

196 μJ

98 μJ

8 μJ

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detailed solution

Correct option is A

At steady state, capacitor acts as open circuit.VA + 3 × 1−14−5 × 3= VB ⇒ VA−VB=26VEnergy stored in capacitor,U=12 CV2 =12 × 10−6 × 262 = 338 μJ

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