Q.
The energy stored in the capacitor in the steady state is
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a
338 μJ
b
196 μJ
c
98 μJ
d
8 μJ
answer is A.
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Detailed Solution
At steady state, capacitor acts as open circuit.VA + 3 × 1−14−5 × 3= VB ⇒ VA−VB=26VEnergy stored in capacitor,U=12 CV2 =12 × 10−6 × 262 = 338 μJ