Questions
Energy stored in a coil of self inductance 40mH carrying a steady current of 2 A is
detailed solution
Correct option is C
U=12Li2⇒U=12×40×10−3×(2)2=0.08JTalk to our academic expert!
Similar Questions
Two different coils have self-inductance mH, . The current in one coil is increased at a constant rate. The current in the second coil is also increased at the same rate. At a certain instant of time, the power given to the two coils is the same. At that time the current, the induced voltage and the energy stored in the first coil are and respectively. Corresponding values for the second coil at the same instant are and respectively. Then
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