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Q.

The energy stored in a 50 mH inductor carrying a current of 4 A will be

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a

0.4 J

b

4.0 J

c

0.8 J

d

0.04 J

answer is A.

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Detailed Solution

U=12Li2=12×50×10−3×(4)2=400×10−3=0.4J
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