The energy that wold be changed of an electron to reduce its De broglie wavelength from 10−10 m to 0.5×10−10m will be :
150 eV
300 eV
450 eV
6000 eV
λ1=1A⇒v1=150(1)2=150v
kE1=150eV
λ2=12A⇒v2=150122=600V
kE2=600eV
ΔK=KE2−KE1
=600−150=450eV