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Questions  

An engine exerts a force  F=(20i^-3j^+5k^)N  and  moves with velocity  v=(6i^+20j^-3k^)ms-1. The power of the engine (in watt) is

a
45
b
75
c
20
d
10

detailed solution

Correct option is A

Power of the engine,P=F·v=(20i^-3j^+5k^)·(6i^+20j^-3k^)= 120 - 60 - 15 = 45 W

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