An engine of one metric ton is going up an inclined plane 1 in 2 at the rate of 36 km/hr. If the coefficient of friction is (1/√3), the power of the engine in watt is

The situation is shown in fig,Power P=F×VGiven v=36km/hr=36×518m/sF=mgsin⁡θ+f=mgsin⁡θ+μmgcos⁡θ =mg(sin⁡θ+μcos⁡θ) =1000×9⋅8(0⋅5+13×32) (∵sin⁡θ=12 and cos⁡θ=32) =9800N∴P=9800×10=98k watt.