An engine pumps up 100 kg of water through a height of 10 m in 5 s. Given that the efficiency of the engine is 60% . If  g=10ms−2, the power of the engine is

Work output of engine = mgh =  100×10×10=104JEfficiency (η) = outputinput    ∴ Input energy =  outputη=10460×100=1056J∴ Power = input energytime=105​/​65=10530=3.3 kW