An engine pumps up 100 kg of water through a height of 10 m in 5 s. Given that the efficiency of the engine is 60% . If g=10ms−2, the power of the engine is
3.3 kW
0.33 kW
0.033 kW
33 kW
Work output of engine = mgh = 100×10×10=104JEfficiency (η) = outputinput ∴ Input energy = outputη=10460×100=1056J∴ Power = input energytime=105/65=10530=3.3 kW