An engine pumps up 100 kg of water through a height of 10 m in 5 s. Given that the efficiency of the engine is 60% . If  g=10ms−2, the power of the engine is

Work output of engine = mgh = 100×10×10=104J Efficiency (η)= output  input  ∴ Input energy = outupt η=10460×100=1056J∴ Power = input energy  time =105/65=10530=3.3kW