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Q.

An engine pumps up 100 kg of water through a height of 10m in 5s. Given that the efficiency of the engine is 60%, What is the power of the engine             ( Take g= 10ms-2)

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a

33kW

b

3.3kW

c

0.33kW

d

0.033kW

answer is B.

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Detailed Solution

Power used to pump the water =  mght=100×10×105                                         Power   =2000W  given efficiency = 60% ⇒60% Power of engine=2000 watt ⇒60100Power of engine=2000 watt ⇒Power of engine=2000×10060=3.3kW
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