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Q.

An engine pumps water continuously through a hole. Speed with which water passes through the hole nozzle is v, and k is the mass per unit length of the water jet as it leaves the nozzle. Find the rate at which kinetic energy is being imparted to the water.

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a

12kv2

b

12kv3

c

v22k

d

v32k

answer is B.

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Detailed Solution

mass per unit length of water jet is K = MassLength=dmdx,                                                                    v = speed of water                                 Kinetic energyKE = 12mv2 differentiate with respect to time,                                                              ddt(KE) = 12 (dmdt)  v2divide and multiply with dx,                                                               ddt(KE)    = 12(dmdx.dxdt)   v2  rate at which kinetic energy is being imparted to the water   =  kvv22 = kv32
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