An engine pumps water continuously through a hole. Speed with which water passes through the hole nozzle is v, and k is the mass per unit length of the water jet as it leaves the nozzle. Find the rate at which kinetic energy is being imparted to the water.
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a
12kv2
b
12kv3
c
v22k
d
v32k
answer is B.
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Detailed Solution
mass per unit length of water jet is K = MassLength=dmdx, v = speed of water Kinetic energyKE = 12mv2 differentiate with respect to time, ddt(KE) = 12 (dmdt) v2divide and multiply with dx, ddt(KE) = 12(dmdx.dxdt) v2 rate at which kinetic energy is being imparted to the water = kvv22 = kv32