Questions
Equal charges q are placed at the vertices A and B of an equilateral triangle ABC of side a. The magnitude of electric field at the point C is
a
q4πε0a2
b
2q4πε0a2
c
3q4πε0a2
d
q2πε0a2
detailed solution
Correct option is C
EA=EB=k⋅qa2So, Enet=EA2+EB2+2EAEBcos60∘=3k⋅qa2⇒Enet=3q4πε0a2Talk to our academic expert!
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