Equal current i flows in two segments of a circular loop in the direction shown in figure. Radius of the loop is r. The magnitude of magnetic field induction at the centre of the loop is
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a
zero
b
μ0iθ3πr
c
μ02πir(π−θ)
d
μ02πir(2π−θ)
answer is C.
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Detailed Solution
Magnetic field induction at O due to current through ACB is B1=μ0iθ4πrIt is acting perpendicular to the paper downwards. Magnetic field induction at O due to current through ADB isB2=μ04πi(2π−θ)rIt is acting perpendicular to paper upwards.∴ Total magnetic field at O due to current loop is B=B2−B1=μ04πir(2π−θ)−μ04πirθ =μ02πir(π−θ)