Equal masses of three liquids A, B  and C have temperatures 100C, 250C and 400C, respectively. If A and B are mixed, the mixture has a temperature of 150C. If B and C are mixed, the mixture has a temperature of 300C. If A and C are mixed, the mixture will have a temperature of

When A and B are mixed,mcA(15−10)=mcB(25−15) or cAcB=2                      …(i)When B and C are mixed,mcB(30−25)=mcC(40−30) or cBcC=2                   …(ii)From Eqs. (i) and (ti), we get cAcC=4Now, let  θ be the equilibrium temperature when A and C are mixed.Then,   mcA(θ−10)=mcC(40−θ) or    4(θ−10)=40−θ Using⁡cAcC=4or    θ=16∘C