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Equal temperature difference exists between the ends of two metallic rods 1 and 2 of equal length. Their thermal conductivities are K1 and K2 and cross-sectional areas are respectively A1 and A2 The condition for equal rate of heat transfer will be

a
K1A2=K2A1
b
K1A2=K22A1
c
K1A1=K2A2
d
K1A12=K2A22

detailed solution

Correct option is C

The rate of flow of heat is given by Qt=KAT1−T2lSince [T1 - T2) and / are the same for two rods, the rate of flow of heat will be the same, if K1A1=K2A2

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