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Q.

Equal temperature difference exists between the ends of two metallic rods 1 and 2 of equal length. Their thermal conductivities are K1 and K2 and cross-sectional areas are respectively A1 and A2 The condition for equal rate of heat transfer will be

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a

K1A2=K2A1

b

K1A2=K22A1

c

K1A1=K2A2

d

K1A12=K2A22

answer is C.

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Detailed Solution

The rate of flow of heat is given by Qt=KAT1−T2lSince [T1 - T2) and / are the same for two rods, the rate of flow of heat will be the same, if K1A1=K2A2
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