First slide
Conduction
Question

Equal temperature difference exists between the ends of two metallic rods 1 and 2 of equal length. Their thermal conductivities are K1 and K2 and cross sectional  areas are resepctively A1 and A2. The condition for equal rate of heat transfer will be

Easy
Solution

\large \frac Qt=\frac {kA(\theta_1-\theta_2)}{l}
kA = constant; k1A1 = k2A2
 

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