Questions
The equation of an equipotential line in an electric field is y = 2x, then the electric field Strength vector at (1, 2) may be
a
4i^+3j^
b
4i^+8j^
c
8i^+4j^
d
−8i^+4j^
detailed solution
Correct option is D
Field lines will be perpendicular to equipotential surface . Slope of equipotential surface m1=2 and slope of electric field lines is m2 .therefore m1×m2 =-1 ⇒m2 = -12 .Talk to our academic expert!
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Work done in moving a positive charge on an equipotential surface is
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