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Q.

The equation of motion of a particle executing simple harmonic motion is a+16π2x = 0. In this equation, a is the linear acceleration in m/s2 of the particle at a displacement x in meter. The time period in simple harmonic motion is:

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a

34sec

b

12sec

c

1 sec

d

2 sec

answer is B.

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Detailed Solution

a = -16π2xStandard equation of SHM is:A =-ω2xHence, comparing two equations, we get,ω = 4πT = 2πω= 2π4π = 12sec
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