The equation of motion of a particle executing simple harmonic motion is a a+16π2x=0. In this equation, a is the linear acceleration in m/s2 of the particle at a displacement x in meter. The time period in simple harmonic motion is

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14sec

12sec

1 sec

2sec

answer is B.

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Detailed Solution

a=−16π2xStandard equation of SHM is:a=−ω2xHence, comparing two equations, we get ω=4π and T=2πω=2π4π=12sec

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