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Questions  

The equation of motion of a particle executing simple harmonic motion is given by   a+36π2x=0, where a  is acceleration and x is displacement. Then, its frequency of  oscillation is (in hertz)

a
3
b
6
c
9
d
4

detailed solution

Correct option is A

A simple harmonic motion can be represented by the equation  a=−ω2x . Comparing the given equation a+36π2x=0 in the above form, we get ω2=36π2 . Taking square root on both sides  ω=6πUsing the relation  ω=2πf,  6π=2πfThe frequency of oscillation f=3Hz

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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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