Q.

The equation of motion of a projectile are x=4tmetre and y=10t−5t2 metre. The horizontal range of projectile  is

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a

8m

b

2 m

c

8.5 m

d

7.5 m

answer is A.

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Detailed Solution

x=4t∴ux=4y=10t−5t2∴uy=10,g=10R=2uxuyg=2×4×1010=8m.
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