Q.

The equation of motion of a projectile is y = ax-bx2 where a and b are constants of motion. Match the quantities of Column - I with the relations of Column - II and mark the correct choice from the given codes.Codes

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a

i-p, ii-q, iii-r, iv-s

b

i-s, ii-p,iii-q, iv-r

c

i-s, ii-p, iii-r, iv-q

d

i-p, ii-s, iii-r, iv-q

answer is C.

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Detailed Solution

Comparing given equation, y = ax-bx2 with the equation of projectile motiony = x tan θ- gx22u2cos2θWe get, tan θ = a-------(i)       g sec2θ2u2 = b----(ii)or u2 = g(1+tan2θ)2b = g(1+a2)2b    (Using (i)or u = [g(1+a2)2b]Here i-s.Horizontal range = u2sin2θg = 2u2sinθ cosθ g                          = = 2u2cos2θg×tanθ = ab                                               (Using (i) and (ii))Hence ii-p.Maximum height = u2sin2θ2g = u2cos2θ2g×tan2θ                          = 2u2cos2θ4g×tan2θ = a24b                                              (Using (i) and (ii))Hence iii-r.From (ii), b = g2u2cos2θor u2cos2θ = g2b or u cos θ = g2b          (iii)Time of flight = 2u sin θg=2gu cosθ× tanθ                    = 2gg2b×a = a2bg                                           (Using (i) and (iii))Hece iv-q
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