The equation of motion of projectile $$isy=12x$$−(3/4)x2The$$ horizontal component of velocity is $$3$$ $$m/s$$. What is the range of projectile ? $$(g$$ $$=$$ $$1.0$$ m $$/$$ $$s2)

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Infinity Learn · Accepted Answer

Given that,  $$y=12x$$−$$(3/4)x2$$∴     $$dydt=12dxdt$$−$$32xdxdt$$ At  $$x=0$$, $$dydt=12dxdtIf$$ angle of projection be θ, $$then(dy/dt)(dx/dt)=$$$$tan$$⁡θ$$=12If$$ u is initial velocity of projection, then ucos⁡θ$$=3Therefore$$,  $$tan$$⁡θ×$$(ucos$$⁡θ$$)=36or$$        usin⁡θ$$=36Now$$,   $$R=u2sin$$⁡$$2$$θ$$g=u2$$×$$2sin$$⁡θ$$cos$$⁡θ$$g=2(usin$$⁡θ$$)(ucos$$⁡θ$$)g=2$$×$$36$$×$$310=21$$⋅$$6cm$$

The equation of motion of projectile is
$y = 12 x - (3 / 4) x^{2}$
The horizontal component of velocity is 3 m/s. What is the range of projectile ? (g = 1.0 m / s²)

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The equation of motion of projectile isy=12x−(3/4)x2The horizontal component of velocity is 3 m/s. What is the range of projectile ? (g = 1.0 m / s2)

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The equation of motion of projectile is
$y = 12 x - (3 / 4) x^{2}$
The horizontal component of velocity is 3 m/s. What is the range of projectile ? (g = 1.0 m / s²)