The equation, of motion of a projectile is $$y=12x$$−$$34x2$$. The horizontal component of velocity is $$3$$ $$m/s$$. Given g $$=$$ $$10$$ $$m/s2$$. What is the range of the projectile ?

Question

The equation, of motion of a projectile is $$y=12x$$−$$34x2$$. The horizontal component of velocity is $$3$$ $$m/s$$. Given g $$=$$ $$10$$ $$m/s2$$. What is the range of the projectile ?

Infinity Learn · Accepted Answer

$$y=12x$$−$$34x2dydt=12dxdt$$−$$32xdxdtor$$      $$dydt=12dxdt$$ at $$x=0or$$      $$dydt/dxdt=12$$ or $$tan$$⁡θ$$=12$$       ….. $$(1)Given$$,      ucos⁡θ$$=3$$            ….$$(3)Now$$,               $$R=u2sin$$⁡$$2$$θ$$g=2u2sin$$⁡θ$$cos$$⁡θ$$g=2(usin$$⁡θ$$)(ucos$$⁡θ$$)g=2$$×$$3$$×$$3610=21.6m$$

The equation, of motion of a projectile is $y = 12 x - \frac{3}{4} x^{2}$ . The horizontal component of velocity is 3 m/s. Given g = 10 m/s². What is the range of the projectile ?

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The equation, of motion of a projectile is y=12x−34x2. The horizontal component of velocity is 3 m/s. Given g = 10 m/s2. What is the range of the projectile ?

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The equation, of motion of a projectile is $y = 12 x - \frac{3}{4} x^{2}$ . The horizontal component of velocity is 3 m/s. Given g = 10 m/s². What is the range of the projectile ?