Equation of a progressive wave is given by
$y = 0 .2 cosπ (0 .04 t + . 02 x - \frac{π}{6})$
The distance is expressed in cm and time in second. What will be the minimum distance between two particles having the phase difference of $π$ /2

Question

Infinity Learn · Accepted Answer

Comparing with $$y=acos($$ω$$t+$$$$kx$$−φ$$)$$, We get  $$k=2$$πλ$$=0.02$$ ⇒ λ$$=100$$ cmAlso, it is given that phase difference between  particles Δφ$$=$$π$$2$$. Hence path difference between them Δ$$=$$λ$$2$$π×Δφ$$=$$λ$$2$$π×π$$2=$$λ$$4=1004=25$$ cm

Equation of a progressive wave is given by
$y = 0 .2 cosπ (0 .04 t + . 02 x - \frac{π}{6})$
The distance is expressed in cm and time in second. What will be the minimum distance between two particles having the phase difference of $π$ /2

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Equation of a progressive wave is given by y=0.2cosπ0.04t+.02x−π6The distance is expressed in cm and time in second. What will be the minimum distance between two particles having the phase difference of π/2

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Equation of a progressive wave is given by
$y = 0 .2 cosπ (0 .04 t + . 02 x - \frac{π}{6})$
The distance is expressed in cm and time in second. What will be the minimum distance between two particles having the phase difference of $π$ /2