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Q.

Equation of a progressive wave is given by y=0.2cosπ0.04t+.02x−π6The distance is expressed in cm and time in second. What will be the minimum distance between two particles having the phase difference of π/2

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a

4 cm

b

8 cm

c

25 cm

d

12.5 cm

answer is C.

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Detailed Solution

Comparing with y=acos(ωt+kx−φ), We get  k=2πλ=0.02 ⇒ λ=100 cmAlso, it is given that phase difference between  particles Δφ=π2. Hence path difference between them Δ=λ2π×Δφ=λ2π×π2=λ4=1004=25 cm
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