Question

The equation of projectile is $Y = \sqrt{3} X - \frac{1}{2} g X^{2}$ The velocity of projection is

Moderate

Solution

Comparing with $y = x \tan θ - \frac{g x^{2}}{2 u^{2} \cos^{2} θ}$ we have
$\tan θ = \sqrt{3} or θ = 60 ° and u^{2} \cos^{2} θ = 1$
or $u = \sec θ = \sec 60 ° = 2 {ms}^{- 1}$

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