The equation of stationary wave along a stretched string is given by y=5sinπx3cos40πt, where x and y are in cm and t in second. The separation between two adjacent nodes is
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a
1.5 cm
b
3 cm
c
6 cm
d
4 cm
answer is B.
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Detailed Solution
On comparing the given equation with standard equation y=2asin2πxλcos2πvtλ⇒2πxλ=πx3⇒λ=6Separation between two adjacent nodes = λ2=3 cm