Questions
Equation of trajectory of a particle projected from a point on ground is where x and y are in metre. If , velocity of projection is
detailed solution
Correct option is A
y=x1−x240Comparing this equation with the standard equation y=xtanα1−xR, We gettanα=1⇒α=450and Range = 240 mNow u2gsin2α=240⇒u210sin(2×450)=240⇒u=206m/sTalk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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