Questions
The equation of trajectory of a projectile is given as . The maximum height of projectile is (Symbols have usual meanings and SI unit)
detailed solution
Correct option is C
y=2x−xh2 dydx=0⇒ dydx=2−2x2=0When y=hmax b ⇒x=2m∴hmax=2×2−2×22 =2mTalk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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