The equation of trajectory of a projectile is given as y=2x−x22. The maximum height of projectile is (Symbols have usual meanings and SI unit)
4 m
1 m
2 m
10 m
y=2x−xh2 dydx=0⇒ dydx=2−2x2=0When y=hmax b ⇒x=2m∴hmax=2×2−2×22 =2m