Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Equation of a transeverse wave propagating in a string is y=2sin50πt−10πxmm. Where x is in metre. If at t = 0, elastic potential energy stored in the string at x = 10/4 cm is 2 J/m, what is the elastic potential energy stored in the string at x = 10/3 cm?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

1 J/m

b

6 J/m

c

8 J/m

d

4 J/m

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

y=2sin50πt−10πxmm∴ ∂y∂x=−20.cos50πt−10πxAt t = 0, ∂y∂x=−20πcos10πxNow elastic potential energy stored per unit length is proportional to ∂y∂x2∴ u2u1=cos210πx2cos210πx1=cos210π×104×100cos210π×103×100⇒u22=cos2π4cos2π3⇒u2=4 J/m
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring