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Q.

The equation of a transverse wave travelling on a rope is given by y = 10sinπ(0.01x-2.00t) where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about

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a

63 cm/s

b

75 cm/s

c

100 cm/s

d

121 cm/s

answer is A.

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Detailed Solution

The given equation is y = 10 sin π(0.01πx-2πt)Hence ω = coefficient of t = 2π⇒ Maximum speed of the particle vmax = aω = 10×2π= 10×2×3.14 = 6.28 = 63 cm/s
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