Q.

The equation of a transverse wave travelling on a rope is given by y = 10 sin π(0.01x - 2.00t) where y and x are in centimetres and t in seconds. The maximum transverse speed of a particle in the rope is about

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a

63 cm/s

b

75 cm/s

c

10 cm/s

d

121 cm/s

answer is A.

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Detailed Solution

Standard equation of travelling wave y = A sin(kix - ωt)   By comparing with the given equation  y = 10 sin(0.01 πx - 2πt)  A = 10 cm, ω = 2π Maximum particle velocity = Aω = 2π  × 10 = 63 cm/s
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