Equation of travelling wave on stretched string of linear density 5g/m is y=0.03sin450t−9x where distance and time are measured in S.I units . The tension in the string is

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10N

12.5N

7.5N

answer is B.

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Detailed Solution

y=0.03sin450t−9x Wave Speed : v=ωk=4509=50 m/s Also, wave speed = v = Tμ=T5×10−3 ⇒50 = T5×10−3 ⇒T=12.5N

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