First slide

Travelling wave

Question

Equation of travelling wave on stretched string of linear density $5 g / m$ is $y = 0.03 \sin (450 t - 9 x)$ where distance and time are measured in S.I units . The tension in the string is

Moderate

A

10N
B

12.5N
C

7.5N
D

5N

Solution

$y = 0.03 \sin (450 t - 9 x) W a v e S p e e d : v = \frac{ω}{k} = \frac{450}{9} = 50 m / s A l s o, w a v e s p e e d = v = \sqrt{\frac{T}{μ}} = \sqrt{\frac{T}{5 \times 10^{- 3}}} \Rightarrow 50 = \sqrt{\frac{T}{5 \times 10^{- 3}}} \Rightarrow T = 12.5 N$

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