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Q.

The equation of a wave traveling on a string is given by y=8sin[(5m−1)x−(4s−1)t] . Then

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a

Velocity of wave is 0.8 ms

b

The displacement of a particle of the string at t=0  and x=π30m from the mean position is 4 m

c

The displacement of a particle from the mean position at t=0, x=π30m is 8 m

d

Both  A & B

answer is D.

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Detailed Solution

Given y=8sin[(5m−1)x−(4s−1)t] …(1) Wave equation y=Asin(kt−ωx)...(2) Compare (1) & (2)ω=4 s−1   k=5 s−1 We know ϑ=ωk=45=0.8 Position at t=0   x=π30 m y=8sin[5(π30)−4(0)] y=8sinπ6 y=8×12 y=4m
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