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Q.

An equiconvex lens is made of glass of refractive index 1.5 and its focal length in air is 0.2m . If it acts as a concave lens of 0.5 m focal length when dipped in a liquid, the velocity of light in the liquid is

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a

1.6×108ms−1

b

2.3×108ms−1

c

3.5×108ms−1

d

3×108ms−1

answer is A.

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Detailed Solution

ffℓ=(μgμl−1)μg-1 0.2−0.5=(32μℓ−1)1/2μℓ=158μ=cv⇒v=3×108×815=1.6×108ms−1
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