An equilateral prism ABC is placed in air with its base side BC lying horizontally along x-axis. A light ray 3z+x=10 is incident at a point P on face AB of the prism.If μ for the prism is 32 , then net deviation of the ray as it emerges out of the prism is
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a
60o
b
30o
c
90o
d
180o
answer is A.
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Detailed Solution
For μ=32, total internal reflection takes place at AC. From geometry, it in clear that ray in perpendicular incident on BC, so net deviation = 180o-120o=60o, only at AC.