An equilateral triangular loop ADC having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the paper (figure). At time t = 0, side DC of the loop is at edge of the magnetic field.
The induced current (i) versus time (t) graph will be as

Question

An equilateral triangular loop ADC having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the paper (figure). At time t = 0, side DC of the loop is at edge of the magnetic field.

The induced current (i) versus time (t) graph will be as

Infinity Learn · Accepted Answer

Let $$2a$$ be the side CD of the triangle and b be the length AE.    $$AHAE=GHEC$$⇒$$GH=AHAEEC$$ ⇒   $$GH=(b$$−$$vt)b$$⋅$$a=a$$−abvt∴    $$FG=2GH=2a$$−abvt∴     Induced emf, $$e=Bv(FG)=2Bva$$−abvt∴     Induced current, $$i=eR=2BvRa$$−abvt or     $$i=k1$$−$$k2tThus$$ $$i-t$$ graph is a straight line with negative slope and positive intercept.

An equilateral triangular loop ADC having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the paper (figure). At time t = 0, side DC of the loop is at edge of the magnetic field.
The induced current (i) versus time (t) graph will be as

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An equilateral triangular loop ADC having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the paper (figure). At time t = 0, side DC of the loop is at edge of the magnetic field.The induced current (i) versus time (t) graph will be as

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

An equilateral triangular loop ADC having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the paper (figure). At time t = 0, side DC of the loop is at edge of the magnetic field.
The induced current (i) versus time (t) graph will be as