First slide

Simple harmonic motion

Question

At the equilibrium position of a particle executing SHM

Moderate

A

restoring force acting on the particle is zero
B

the velocity of the particle is maximum
C

potential energy is minimum
D

all the above

Solution

$F o r c e = F = - k x k i s f o r c e c o n s \tan t x i s d i s p l a c e m e n t a t x = 0, F o r c e = - k (0) F = 0$
$v e l o c i t y o f p a r t i c l e, v = ω \sqrt[]{(A^{2} - x^{2})} v^{2} = ω^{2} (A^{2} - x^{2}) a t x = 0, K i n e t i c e n e r g y o f p a r t i c l e = \frac{1}{2} m ω^{2} (A^{2} - 0^{2}) = m a x i m u m P E = \frac{1}{2} m ω^{2} (x^{2}) a t x = 0, P E = 0$
Potential energy=PE=minimum

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