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Questions  

The equivalent inductance of two inductances is 2.4 H when connected in parallel and 10 H when connected in series. The difference between the two inductances is

a
2 H
b
3 H
c
4 H
d
5 H

detailed solution

Correct option is A

Ls=L1+L2=10H                …(i)Lp=L1L2L1+L2=2.4H             …(ii)On solving (i) and (ii), L1L2=24 …(iii)Also L1-L22=L1+L22-4L1L2⇒L1-L22=(10)2-4×24=4⇒L1-L2=2H

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