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Q.

The equivalent inductance of two inductances is 2.4 H when connected in parallel and 10 H when connected in series. The difference between the two inductances is

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a

2 H

b

3 H

c

4 H

d

5 H

answer is A.

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Detailed Solution

Ls=L1+L2=10H                …(i)Lp=L1L2L1+L2=2.4H             …(ii)On solving (i) and (ii), L1L2=24 …(iii)Also L1-L22=L1+L22-4L1L2⇒L1-L22=(10)2-4×24=4⇒L1-L2=2H
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