The equivalent resistance of two resistors are R1=(100±2)Ω,R2=(300±4)Ω and R3=(20±1)Ω. The equivalent resistance when they are connected in series is

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(210±6) Ω

(100±5)Ω

(42±0.7) Ω

(420±7)Ω

answer is D.

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Detailed Solution

R=R1+R2+R3=100+300+20=420Ω ΔR=ΔR1+ΔR2+ΔR3=2+4+1=7 Ω R±ΔR=(420±7) Ω

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