First slide
Gravitaional potential energy
Question

The escape velocity of a body from the surface of the earth is nearly

Easy
Solution

\large V_e=\sqrt {\frac {2GM}{R}}
\large V_e=\sqrt {\frac {2GM}{R}}=\sqrt {2.\frac {GM}{R^2}.R}=\sqrt {2gR}
\large =\sqrt {2\times9.8\times64\times10^5}m/s=11.2km/hr

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