The escape velocity for a body projected vertically upwards from the surface of earth is 11 km/s. If the body is projected at an angle of 45. with the vertical, the escape velocity will be

• A

  $\frac{11}{\sqrt{2}}\mathrm{km}/\mathrm{s}$

• B

  $11\sqrt{2}\mathrm{km}/\mathrm{s}$

• C

   22 km/s

• D

   11 km/s