The escape velocity for a body projected vertically upwards from the surface of earth is 11.2 km/s. If the body is projected at an angle of ${45}^o$ with the vertical, the escape velocity will be

• A

  $\frac{11}{\sqrt{2}}km\text{}/\text{}s$

• B

  $11\sqrt{2}km\text{}/\text{}s$

• C

  $22 km/s$

• D

  $11.2 km/s$