First slide

Gravitaional potential energy

Question

The escape velocity corresponding to a planet of mass M and radius R is 50 km/sec. If the planet's mass and radius were 4M and R respectively then the corresponding escape velocity would be

Easy

A

100 km/sec
B

50 km/sec
C

200 km./sec
D

25 km/sec

Solution

The escape velocity v_e is given by
$V_{e} = \sqrt{(\frac{2 GM}{R})} \cdot So 50 = \sqrt{(\frac{2 GM}{R})}$
In second case
$\begin{array}{l} v_{e}^{'} = {[\frac{2 G (4 M)}{R}]}^{1 / 2} = 2 {[\frac{2 GM}{R}]}^{1 / 2} \\ = 2 \times 50 = 100 km / \sec \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App